This week's book giveaway is in the Servlets forum. We're giving away four copies of Murach's Java Servlets and JSP and have Joel Murach on-line! See this thread for details.

6 ostriches and 11 pigs. The Math: x = # of ostrich legs, x/2 = # of ostriches y = # of pig legs, y/4 = # of pigs x + y = 56 x/2 + y/4 = 17 y = 56 - x x/2 + (56 - x)/4 = 17 4(x/2 + (56 - x)/4) = 4 * 17 2x + 56 - x = 68 x = 12 y = 56 - 12 = 44 x/2 = 6 y/4 = 11 [ September 10, 2003: Message edited by: Jason Menard ]

HS Thomas
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Congrats. I did it the usual (longer) way using math. Here is a solution that uses pure logic. Each animal has two hind legs, so 17 heads means 34 hind legs total. The remaining 22 legs must be the front legs of 11 four-legged pigs. Therefore 11 heads belong to the pigs and the remaining 6 heads belong to ostriches. regards