[Easy]find the angles between the hands

I have taken this from one of the competition.I have sloved this ,wanted to check in how many ways this can be done.
Write a program: Given a time,return the angles between the hands of the clock.[first is hour hand to minute ,minute to second,second to hour]
Return values should be of type 'float'.
Example
0)12:00:00
returns: 0,0,0
1)9:30:00
returns 105,180,75

It could be me, but I think there is some discrepancy here.
Is the angle between the hands measured clockwise? In which case :-
12:00:00 and 00:00:00 should have the same angle readings. I am just not sure that it is 0 0 0.
How should the program handle 24 hours ?
regards

you can calculate each hand's position based on the time.
the second hand is at 360 * (seconds / 60) degrees
the minute hand is at 360 * (minutes * 60 + seconds) / 3600
the hour hand... whatever
then, once you know the position of each individual hand, you can just subtract... and maybe take the absolute value....
this is just off the top of my head, so i haven't worked out all (well, any) of the details, so forgive me if anything isn't exactly right...
f