Hi, guys: I wanted to put some code in tomcat/webapps/, I got a folder named 'test' within 'webapps', such as: webapps/test/, then I put .class files to webapps/test/WEB-INF/classes/; for example: webapps/test/WEB-INF/classes/1.class; webapps/test/WEB-INF/classes/A/2.class; webapps/test/WEB-INF/classes/B/3.class; The process flow is 1 call 2, then call 3. I worte the file web.xml in WEB-INF; after starting tomcat, I used http://localhost:8080/test/1; I got 1, but the browser can not find 2. I do not know why. Acctually, I wrote <servlet-class> A.2</servlet-class>. So, Do you know how to descript the web.xml.
I know you guys have a lot of good idea, please give me some hint. or give me some reference files. Thanks!
The location of the files in the WEB-INF/classes directory has to be exactly that which satifies classpath rules - If you have a file: WEB-INF/classes/A/1.class, then its package name must be specified in the source code as "package A;" and its class name must, of course be "public class 1 {..." (well, actually a legal java name)
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mocca az
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In other words your web.xml should look something like this <web-app> <servlet> <servlet-name>2</servlet-name> <servlet-class>A.2</servlet-class> </servlet> <servlet-mapping> <servlet-name>2</servlet-name> <url-pattern>2</url-pattern> </servlet-mapping> </web-app> to invoke it you should have http://localhost:8080/2
I agree. Here's the link: http://ej-technologies/jprofiler - if it wasn't for jprofiler, we would need to
run our stuff on 16 servers instead of 3.
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