# math prob: someone plz. answer

Vikrama Sanjeeva

Ranch Hand

Posts: 756

posted 10 years ago

- 0

Hi,

I am stuck to one problem...

Problem:

To enroll 300 students for 10 courses, 4 hrs is required. How mucg time is required to enroll X students for Y courses

Bye,

Viki.

I am stuck to one problem...

Problem:

To enroll 300 students for 10 courses, 4 hrs is required. How mucg time is required to enroll X students for Y courses

Bye,

Viki.

Count the flowers of your garden, NOT the leafs which falls away!

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Jason Menard

Sheriff

Posts: 6450

Ryan McGuire

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Posts: 1048

4

posted 10 years ago

Assumption: Registering one student for one course is the basic unit of work. So registering one student for ten courses takes the same time as registering ten students for one course each.

300 students x 10 courses for each = 3000 studentCourses

3000 studentCourse / 4 hours = 750 studentCourse/hour

For any number of courses and students, just divide by this work rate.

Time needed = X x Y / 750 studentCourses/hour

Ryan

- 0

Originally posted by Vikrama Sanjeeva:

To enroll 300 students for 10 courses, 4 hrs is required. How mucg time is required to enroll X students for Y courses

Assumption: Registering one student for one course is the basic unit of work. So registering one student for ten courses takes the same time as registering ten students for one course each.

300 students x 10 courses for each = 3000 studentCourses

3000 studentCourse / 4 hours = 750 studentCourse/hour

For any number of courses and students, just divide by this work rate.

Time needed = X x Y / 750 studentCourses/hour

Ryan

Arjunkumar Shastry

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Posts: 986

Ryan McGuire

Ranch Hand

Posts: 1048

4

posted 10 years ago

That's what I said. (2XY/25)minutes == (XY/750)hours

edit:

And that would have clearer if I used more parentheses. I shoudl have said...

Time needed = X x Y / (750 studentCourses/hour)

...which reduces to (XY hours)/(750 Student*Courses)

...or if you leave out the student and course units... (XY/750) hours

Ryan

[ April 14, 2005: Message edited by: Ryan McGuire ]

- 0

Originally posted by Arjunkumar Shastry:

I got 2*X*Y/25 minutes.

That's what I said. (2XY/25)minutes == (XY/750)hours

edit:

And that would have clearer if I used more parentheses. I shoudl have said...

Time needed = X x Y / (750 studentCourses/hour)

...which reduces to (XY hours)/(750 Student*Courses)

...or if you leave out the student and course units... (XY/750) hours

Ryan

[ April 14, 2005: Message edited by: Ryan McGuire ]

Vikrama Sanjeeva

Ranch Hand

Posts: 756

posted 10 years ago

- 0

Hi,

Thank you guyz

Bye,

Viki.

Thank you guyz

Bye,

Viki.

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