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Enigma

 
Sameer Jamal
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Assign all-different values to the letters in these words to make the equality true in English.

ONE + ONE + TWO + TWO + THREE + ELEVEN = TWENTY
 
Ryan McGuire
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Originally posted by Sameer Jamal:
Assign all-different values to the letters in these words to make the equality true in English.

ONE + ONE + TWO + TWO + THREE + ELEVEN = TWENTY


Surely you find or come up with a more original problem than this! As a Programming Diversion, this is similar enough to previous questions that it's no longer interesting. See this thread for instance.

...or am I just being overly picky?
 
Reid M. Pinchback
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I'd go for picky, if only because Sameer at least made the attempt at creating something diverting. Kinda nice to have a few relaxed forums on the site without all the energy of the heated debates that exist elsewhere. Maybe we should cut him some slack.
 
Ryan McGuire
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Originally posted by Reid M. Pinchback:
I'd go for picky, if only because Sameer at least made the attempt at creating something diverting. Kinda nice to have a few relaxed forums on the site without all the energy of the heated debates that exist elsewhere. Maybe we should cut him some slack.


I will admit that I liked the 9+9x9 question. I also rather liked his fat software engineer "Distance problem."

And I'm not suggesting that the good Mr. Jamal stop posting here -- just that I'm sure he can do better than letter->digit substitution puzzles. He has before.

Ryan
 
David O'Meara
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Does that mean you already solved it?
 
Sameer Jamal
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Gist: If something interests you doesn�t mean everybody will find interest in it. It is hard to find things, which suits all.
 
Stan James
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The circus works because every year there is a new bunch of kids who haven't seen it yet. If you've seen a puzzle before, just ignore it. It will be new to somebody.
 
Reid M. Pinchback
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Originally posted by Stan James:
The circus works because every year there is a new bunch of kids who haven't seen it yet. If you've seen a puzzle before, just ignore it. It will be new to somebody.


Either that, or pretend you have the memory of a manager. Wait 15 minutes. Voila, new puzzle.

 
Ryan McGuire
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Originally posted by Stan James:
The circus works because every year there is a new bunch of kids who haven't seen it yet. If you've seen a puzzle before, just ignore it. It will be new to somebody.


Even the circus comes only once a year.

But I get your point; carry on.
 
Ryan McGuire
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Originally posted by David O'Meara:
Does that mean you already solved it?


Well since it was in Programming Diversions, I wrote a progam to solve the previous puzzle. Solving this one involves nothing more than replacing the initial data.

Ryan
 
Peter van de Riet
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Originally posted by Sameer Jamal:
ONE + ONE + TWO + TWO + THREE + ELEVEN = TWENTY

Because the V en the R are both occuring once in this puzzle, and also both on the same value (100-fold) this puzzle has no unique solution. For that reason, I think personally this is not a good puzzle.

175+175+601+601+68255+535957=605764
175+175+601+601+68955+535257=605764

2 more solutions if the 0 can stand in front of a number:
085+085+640+640+69155+575258=645863
085+085+640+640+69255+575158=645863

Anyone cares to see the program?
 
Reid M. Pinchback
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Maybe a more interesting "puzzle" would be how to write a program to generate these puzzles, and ensure that they had unique solutions...
 
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