RequestDispatcher and Blank Page

[Eric Baxter]

Hello,

I'm trying to forward the results of a JDBC / servlet call to a JSP. Rather than going to the results JSP I view a blank page. In the address screen is the path of the URL-Pattern in the web.xml file. I'm at wits end
Thanks alot!!

JMSDemo is the context (dir just below webapps)

Starting JSP Page action tag

<form name ="GUIform" method="POST" action="Demo">

Web.xml lines ---

<servlet>
<servlet-name>DemoServlet</servlet-name>
<servlet-class>com.TestDemo.DemoServlet</servlet-class>
  </servlet>
    <servlet-mapping>
  <servlet-name>DemoServlet</servlet-name>
  <url-pattern>/Demo</url-pattern>
  </servlet-mapping>
 

Servlet Code ---

 String address = "/Results.jsp";
 RequestDispatcher dispatcher = getServletContext().getRequestDispatcher(address);
       //dispatcher.forward(request, response); //same results with either line
        dispatcher.include(request, response);

Result -http://localhost:8080/JMSDemo/Demo (BLANK PAGE)

Thanks again!!
E

[Ali Gohar]

<servlet><servlet-name>DemoServlet</servlet-name><servlet-class>com.TestDemo.DemoServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>DemoServlet</servlet-name> <url-pattern>/Demo</url-pattern> </servlet-mapping>

You have mapped the servlet as /Demo and you are using "Demo" in following line instead of /Demo

<form name ="GUIform" method="POST" action="Demo">

Use /Demo instead of Demo and use http://localhost:8080/Demo to access this servlet.

May be this will solve the problem. If not then tell what happens when you change these things

[Eric Baxter]

Thank you for your help.

The answer was multipart.

When I commented out the print statement used when an exception was thrown, the page forwarded correctly.

Thanks again