rd=request.getRequestDispatcher(....) rd.forward(...) //some lines of code.
why is it that the control returns back to the servlet and the code below forward() is also executed?that should be the case only with include().
Joined: Dec 23, 2003
You are just calling a method. When it is done it will return. This is the expected behavior.
From the javadoc for those two methods you can see that the difference is what is/isn't done to the Reqeust and Response objects before dispatching the request.
Joined: Feb 16, 2001
in the code after the call to forward, i throw an exception which should load another error page, which doesnot happen. that is why i am keen to know if the control returns back after forward, coz if it does then the exception must be thrown and the error page must be displayed which is not happening.
Joined: Jul 26, 2004
The de-facto implementation of RequestDesipatcher object defines the following two things
1. "A call to forward() may be used if *only* if no content has previously sent to the client.
2. "No further data can be sent to a client after tha call to forward has completed.
Assuming your rd.forward() worked succesfully, the request moves out of the current scope and moves on to the forwarded resource.
Why don't you try generating the error page from the resource that this call was forwarded to. (assumption : your architecture should be able to support this)
-Divij<br />---------------------------------<br />Weinberg's Law: If builders built buildings the way programmers wrote programs, then the first woodpecker that came along would destroy civilization.