Escape Sequence problem

[Raja Sagar Panamgipalli]

Hi All,
i'm having a problem with compilation at this statement....can anyone plz explain how to go about resolving such errors.

out.println("<hr><p><a href='\cart\servlet\catalog\'>back to homepage</a></p>");  

ShoppingCart.java:41: illegal escape character out.println("<hr><p><a href='\cart\servlet\catalog\'>back to homepage
</a></p>");
^
ShoppingCart.java:41: illegal escape character out.println("<hr><p><a href='\cart\servlet\catalog\'>back to homepage
</a></p>");
^
ShoppingCart.java:41: illegal escape character out.println("<hr><p><a href='\cart\servlet\catalog\'>back to homepage
</a></p>");

thank you so much....

Sagar

[Ben Souther]

URLs use forward slashes not back slashes

 out.println("<hr><p><a href='/cart/servlet/catalog/'>back to homepage</a></p>");   

That should take care of it.

BTW: If you ever do need to put a backslash in a string, just escape it with another backslash

Example:

  System.out.println("c:\\\\windows\\system32"

[ April 24, 2005: Message edited by: Ben Souther ]