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Joined: Dec 17, 2006
Mar 05, 2008 22:29:00
Whenevr i click the link in the homepage that should leads to the
page but its throwing this exception
javax.servlet.ServletException: cannot find message associated with key : dispatcher.forwardException at org.apache.tomcat.facade.RequestDispatcherImpl.doForward() at org.apache.tomcat.facade.RequestDispatcherImpl.forward() at
I would like to know what could be the reason for this exception.
Please help me on this.
[ March 06, 2008: Message edited by: Ben Souther ]
regards,<br /> rajan<br /> SCJP 1.4
Joined: Dec 19, 2007
Mar 06, 2008 00:23:00
How can you use the
to click in home page.
If you are putting
in home page it will direcly
goes to the directed page/jsp.
Put your code properly for that.
Joined: Dec 11, 2004
Mar 06, 2008 03:38:00
That isn't a complete stack trace.
Either post all of it or find the relevant section
(the part of it that shows the line number in your code).
Of course, once you find the relevant section, you probably won't need help
from the list.
How to ask a question...
Simple Servlet Examples
I agree. Here's the link:
How do I catch a user define exception on the client (SOAP/JAX-RPC/WSDL)
Throwing more than one application exception from a ejb interface
Check to see if Exception is thrown
Create an exception
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