Wrapper cannot find servlet class

Hi friends,

I develop a Web Application using JSP/Servlets in where i use MVC. So i had a bean file, a servlet file and ofcourse a JSP page. I already created a user reg file and it works fine. But when i create another servelt to update my table it doesnt work.

However when i compile the code it shows an error like this one..

C:\apache-tomcat-6.0.16\webapps\rmanew\WEB-INF\classes\com\rajk\javacode\servlet
s>javac -classpath c:\apache-tomcat-6.0.16\lib\servlet-api.jar RMAOutServlet.java
RMAOutServlet.java:14: cannot find symbol
symbol : class RMAEntryModel
location: class com.rajk.javacode.servlets.RMAOutServlet
RMAEntryModel model = new RMAEntryModel();
^
RMAOutServlet.java:14: cannot find symbol
symbol : class RMAEntryModel
location: class com.rajk.javacode.servlets.RMAOutServlet
RMAEntryModel model = new RMAEntryModel();
^
2 errors

Where RMAEntryModel is the bean file i used to get and put values.. I already used it in two file named as RMAEntryServlet and RMAProcessServlet. But it doesnt shows any error like this.. Whats wrong is in there. Here i paste my code for your reference.

RMAOutServlet.java
------------------

package com.rajk.javacode.servlets;
 
import java.io.*;
import java.sql.*;
import javax.servlet.*;
import javax.servlet.http.*;
import javax.servlet.http.HttpSession;
 
public class RMAOutServlet extends HttpServlet
{
public void doPost(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException
    {
        RMAEntryModel model = new RMAEntryModel();

String serialno=request.getParameter("serialno");
String replacedsno=request.getParameter("replacedsno");
String customer=request.getParameter("customer");
 String item=request.getParameter("item");
String status=request.getParameter("status");

model.setSerialnumber(serialno);
       model.setReplacedserialnumber(replacedsno);
       model.setCustomer(customer);
       model.setItem(item);
       model.setStatus(status);

try
{

int ra=model.updateOut(serialno,replacedsno,customer,item,status);
if(ra==1)
{
response.sendRedirect("administratorhome.jsp");
}
else
{
}
}
catch(Exception e)
{
throw new ServletException(e.getMessage());
}
}
    public void doGet(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException
    {
       doPost(request,response);
    }
 
}

Anyhelp will be appreciated....

Your classpath is wrong. Make sure RMAEntryModel is in it.

Yes Paul,
the file RMAEntryModel is in the location. Why i am so clear on tis, because i already used the RMAEntryModel in my earlier modules like User Registration, Entry form Servlets.. At that time it works good.. But when i use it for RMAOutServlet, it shows an error like this? Why.. i get stuck with this problem..

javac -classpath c:\apache-tomcat-6.0.16\lib\servlet-api.jar RMAOutServlet.java

This is where you set your classpath. I don't see RMAEntryModel in it. It is not part of the Servlet APi whic his the only other thing you have in your classpath. See this if you are not sure what is going wrong.

Thanks for all,
I resolved my problem regarding classpath.. Now i got a new problem in MySQL query.. So i decided to get my feet on some MySQL...
Thanks for your help