how tto initialize HttpServletRequest

[nimo frey]

How can I obtain the reference of an HttpServletRequest within the sessionCreated-Method of HttpSessionListener?

something like:

public class Listener implements HttpSessionListener {
 
public void sessionCreated(HttpSessionEvent e) {
 
HttpSession session = e.getSession();
 
HttpServletRequest servletRequest = ???
 
..
}

This does not work:

HttpServletRequest servletRequest = session.getServletContext();

Any Ideas?
[ September 08, 2008: Message edited by: nimo frey ]

[Paul Sturrock]

You can't directly initialize an HttpServletRequest. Why are you trying to? What is it you are trying to do?

[nimo frey]

I want to get the methods available of HttpServletRequest.

I want to do something like:

public void sessionCreated(HttpSessionEvent e) {
 

HttpSession session = e.getSession();
..
System.out.println("Session created: " + session);
 
// now method invoking from HttpServletRequest
System.out.println("getRemoteAddr :"   + servletRequest.getRemoteAddr());
..
}

Should I implement a method in my listener:

public void IP( HttpServletRequest req )
    {
        ip = req.getRemoteUser();
    }

then I can call the global String ip in my sessionCreated-Method:

System.out.println("getRemoteAddr :"   + ip);

But this does not work..string is allways null.

any ideas?

[Paul Sturrock]

A session listener is designed to listen to session events. If you want to handle requests a Servlet is the tool you would normally use. If you want functionality accross all requests, a filter is a better choice.

[nimo frey]

As I use JSF and want avoid implementing Servlets directyl, I will try to use filters..

thanks.