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Dan Temple
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Joined: Jul 10, 2001
Posts: 93
I have been using the JQ+ tester which has been worth every penny. However I have come across a question which seems wrong. But since they have been always right before, its probably me that's wrong. here is the question:
If write(0xAABBCCDD) is called on an instance of FileOutputStream, what will be written to the destination of the stream?
They say the answer is -
The byte 0xDD
But this seems wrong: Here is my reasoning, A Byte can only have a max value of 127 and DD is 221 in hex. In binary this is 11011101. Only the low order bits would be retained for a byte which is 1011101 which is 93, or 5D in hex. What am I missing?
Geoffrey Falk
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Joined: Aug 17, 2001
Posts: 171
The byte 0xDD in decimal is -35 (a valid value).

Sun Certified Programmer for the Java 2 Platform
Dan Temple
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Joined: Jul 10, 2001
Posts: 93
Ah yes ... I forgot that high order bit. Thanks for the reply
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