How do I remove decimal part of double?

[Matt Senecal]

There's a function that I'm working with that returns a double with a very long decimal part tacked onto it. The units the double represents are so precise that I can just lose the decimal part. I was thinking of using a StringBuffer to parse the double and remove the offending decimal. Anyone know an easier way to do this?

[Cindy Glass]

Use a DecimalFormat.

[Matt Senecal]

Thanks for the reply. In all honesty, though, that seems to be a lot more complex than my original idea. I'm only dealing with two numbers here, and implementing a DecimalFormat seems to be a bit much.

Originally posted by Cindy Glass:
Use a DecimalFormat.

[Paul Stevens]

You could use a Double and the intValue() or longValue() method of Double.
[This message has been edited by Paul Stevens (edited September 28, 2001).]

[shilpa kulkarni]

or, you can use the NumberFormat class, this way u can set the number of digits after decimal that u want.
here is an example :

import java.text.*;
public class MyNumberFormat{
  public static void main(String[] args){
    try{
      NumberFormat nf = NumberFormat.getInstance();
      nf.setMaximumFractionDigits(2);// set as you need
      String myString = nf.format(1080.4512345);
      System.out.println("string : " + myString);
    }catch(Exception e){
      System.out.println("ex="+e);
    }
  }
}

[Jim Yingst]

If you just want to drop the fractional part entirely and round to the nearest integer, it's quite simple:
<pre> int intVal = (int) doubleVal;</pre>

[This message has been edited by Jim Yingst (edited September 28, 2001).]

[Peter den Haan]

And if you want to round differently, it's almost as simple - explore java.lang.Math (e.g. Math.floor() etc).
- Peter