This week's book giveaway is in the Servlets forum. We're giving away four copies of Murach's Java Servlets and JSP and have Joel Murach on-line! See this thread for details.

Hello, I would be sitting for the programmer exam on saturday and there is only one set of questions I would skip 'cos I don't know. It's a little problem with the declaration of octal and hexadecimal values in java. The Java 2 certification study guide says on page 11 that "The value of 28 may thus be expressed six ways: 28// Decimal value. 034//this is supposed to be in base 8,right? 0x1c} 0x1C} Hexadecimal values. 0X1c} 0X1C} No matter how hard I've tried, I don't seem to understand any except for the first. My calculation of 28 to base 8(the second item on the list) is: 2x81 + 2x80 Which would give; 16 + 2. I'd have expected the result to be 018. But it's 034. The rest I don't even know what to think. I need help here. Can anyone please help me out? Thanks.

You've got a few things turned around. It's 34 which is already in octal - so to see the equivalent decimal value, calculate 3 * 8^1 + 4 * 8^0 = 24 + 4 = 28 (where of course ^ is "to the power of", not the java OR operator) Likewise 0x1C is in hex, so convert to decimal thus: 1 * 16^1 + 12 * 16^0 = 16 + 12 = 28