Entry class problem, add method not working properly.

[Fredrik Komstadius]

I have this weird problem that I can not figure out what do to with. I want to do the following thing with the help of my entry class:

  public boolean add (Object o) {
if (root == -1) {
    tree[root] = new Entry (o, -1);
    size++;
    return true;
} // empty tree
else {
    int temp = root;  // �ndrat
    int comp;
    while (true) {
comp = ((Comparable)o).compareTo (tree[temp].element);
if (comp == 0)
    return false;
if (comp < 0)
    if (tree[temp].left !=-1)
temp = tree[temp].left;
    else {
[B]tree[temp].left = new Entry (o, temp);[/B]
size++;
return true;
    } //tree[temp].left == -1
else if (tree[temp].right !=-1)
    temp = tree[temp].right;
else {
[B]    tree[temp].right = new Entry (o, temp);[/B]
    size++;
    return true;
} // tree[temp].right = -1
    } // while
} //root not -1
    } // method add

The thing is that I get the following error:

incompatible types
found : BinSearchTreeArray.Entry
required: int
tree[temp].left = new Entry (o, temp);

private static class Entry{  //extends AbstractSet
Object element;
int parent,
    left,
    right;
// Postcondition: this Entry object has been initialized from element and
//  parent.
Entry (Object element,int parent) {
    this.element = element;
    this.parent = parent;
} // constructor
    }// class Entry  

I realise this might be a bit much for you guys to take a look at but any help would be greatly appreciated!
[ October 15, 2002: Message edited by: Fredrik Komstadius ]
[ October 15, 2002: Message edited by: Fredrik Komstadius ]

[Ron Newman]

I don't see a declaration for "tree" anywhere in your code, so I don't know what fields it has or what type they are.
Also, you have "extends AbstractSet" in a comment where it won't have any effect.
You certainly cannot assign an Object (such as Entry) to an int.
[ October 15, 2002: Message edited by: Ron Newman ]

[Fredrik Komstadius]

Tree is declared Entry[]Tree.
And yea, starting to see that I'm assigning invalid types to an int. Thanx for the help!