This week's book giveaway is in the Servlets forum.
We're giving away four copies of Murach's Java Servlets and JSP and have Joel Murach on-line!
See this thread for details.
The moose likes Java in General and the fly likes Loop for console input.... Big Moose Saloon
  Search | Java FAQ | Recent Topics | Flagged Topics | Hot Topics | Zero Replies
Register / Login

Win a copy of Murach's Java Servlets and JSP this week in the Servlets forum!
JavaRanch » Java Forums » Java » Java in General
Bookmark "Loop for console input...." Watch "Loop for console input...." New topic

Loop for console input....

Jonathan King

Joined: Jan 28, 2004
Posts: 14
All right guys and gals, I've been working on this for hours now, and I am stuck!! I get a user's choice from console, and perform some actions based on that choice. After, they can enter 'y' to try another menu choice, or any key to exit the program. I have gotten to where the program runs great, and when they choose y to try again, the menu will print, and they can do another choice, but if I want to choose 'y' again, it just ends. I would like to get it to loop so if they press 'y' 1000 times after running a choice (as long as it is not the exit choice) it will print the menu again and they can choose another choise. HOW!!! PLEASE EASE MY FRAZZLED MIND!!! ARGGGHHHH!!!

Sadanand Murthy
Ranch Hand

Joined: Nov 26, 2003
Posts: 382
Your if condition where you check if input is y is the problem. The var input is a String; Strings cannot be compared via the == operator. Look at the String documentation in the API to see what method you need to use.
I noticed that you are setting done = true outside the while loop.

Ever Existing, Ever Conscious, Ever-new Bliss
wood burning stoves
subject: Loop for console input....
Similar Threads
reading a file, then replacing a string...
endless loop
[HOMEWORK] Please need help with java project
Help with printing appointments