How avoid replacement of new line char in regex string replacement?

[Maulin Vasavada]

Hi all,

I have the following code,

public static void test2() {

String newLine = System.getProperty("line.separator");
String TOKEN="TOKEN";
String s = "abc maulin   vasavada";
StringBuffer sb = new StringBuffer();
sb.append(s).append(newLine).
append(s).append(newLine).
append(s);
String s1 = sb.toString();
System.out.println(s1);
s1 = s1.replaceAll("\\s+",TOKEN);
System.out.println(s1);
}

Here the problem is, "\\s+" pattern matches the newlines in the string and replace them with TOKEN. I want every multiple occurance of whitespace chars to be replaced by TOKEN except for newline chars. How can I do that via some regex pattern only?

Alternatively I have to go long way to,
1. first replace all new line with a known token- say TOKEN1 to prevent them from getting replaced via "\\s+" pattern matching.
2. then match "\\s+" pattern and replace all multiple whitespace occurances with single space
3. replace all TOKEN1 back to newline.

Is there any other way via regex pattern we can do this? OR I have to go this long way I mention above?

Regards,
Maulin

[Michael Dunn]

these seem to work OK

s1 = s1.replaceAll("[^\\r\\n&&[\\s]]+",TOKEN);
or
s1 = s1.replaceAll("[ \\t\\x0B\\f]+",TOKEN);

[Maulin Vasavada]

Thanks Michael.

Second one seems more intuitive

Regards,
Maulin