Compare two arraylist

I have one array list having duplicate elemnts but now i want it will show me only unique list ..so what to do ??
shall i put this list in another arraylist?
how?
please with code..
very urgent

Wrong choice of data structure. You should have used a HashMap, which does not allow duplicates and automatically replaces any items already in the Map.

please send me code haow to put that hashtable value into hashmap so that i cant get duplicate record...urgent..

Thanks in advance

A Map isn't right either; you want to use a Set.

ArrayList myList = ...
Set set = new HashSet();
set.addAll(myList);

Now set.iterator() will give you a list of the unique elements, of you can say

ArrayList uniqueList = new ArrayList(set);

to get an ArrayList of them.

No sir , I am showing u my code

ArrayList myList ;
Set set;
ArrayList uniqueList;
myList = new ArrayList();
myList.add((String)childHash.get("ADMD_TO_SRVR_IP_ADRS"));
//in this list i have duplicate 'ADMD_TO_SRVR_IP_ADRS'
set = new HashSet();
set.addAll(myList);
set.iterator();
uniqueList = new ArrayList(set);
System.out.println("uniqueList "+uniqueList);
System.out.println("uniqueList "+uniqueList.size());

Now again it is showing me duplicate 'ADMD_TO_SRVR_IP_ADRS'

Please help me...

Thanks in advance
vivek S.

In the code you're showing me here, myList contains only one item -- the String returned from that "get" call. So the set, and ultimately uniqueList, will also contain only one item.

In any event, if ArrayList contains Strings, then the procedure I've shown you will indeed produce a list of the unique Strings. If it contains some other kind of object, then it will work as long as that class has proper equals() and hashCode() methods that correctly implement your notion of equality for that class.

Note that the iterator() method returns an Iterator over the Set; it's one way to look at the contents of the Set. If you're not going to use the Iterator, there's no need to call iterator()!

Another example of our previous talk (Ernest). Sometimes the API is completely ignored, and I am asking why?

--
:alex |.::the_mindstorm::.

Originally posted by Ali Pope:
Sometimes the API is completely ignored, and I am asking why?

Because it's "urgent."

Originally posted by David Harkness:
Because it's "urgent."

Originally posted by Ali Pope:
Another example of our previous talk (Ernest). Sometimes the API is completely ignored, and I am asking why?

--
:alex |.::the_mindstorm::.

It is said, isn't it? However, I try my best to help people. Usually I make the assumption that people don't know about the documentation that is available and provide a link to it. :roll:

Layne

Probably it should be bundled inside the distro, maybe this will at least make you ask why the download is so large.

--
:alex |.::the_mindstorm::.

i'm already asking why the download is so large.

so what is solution for that i want list of unique io_address in arraylist
pleasse help

Thanks in advance
Vivek s.

I told you the solution. If it's not working for you, then you'll need to give us more details about how you're applying that solution. For example, is io_address a class? If so, does it define a proper equals() and hashCode() method? Or are you just putting Strings in the list? If so, what evidence do you have that there are duplicates in the Set?

//my code
String apl_code_var = null;
String admd_to_srvr_ip_adrs_var = null;
String project_code_var = null;
if (request.getAttribute("server_ip") != null){
iCount = 0;
server_ip = (java.util.Hashtable)request.getAttribute("server_ip");

if (server_ip.size() > 0) {
enumHash = server_ip.elements();
while (enumHash.hasMoreElements()) {
childHash = (java.util.Hashtable)enumHash.nextElement();
project_code_var = (String) childHash.get("PROJECT");
apl_code_var = (String) childHash.get("APL_CODE");
admd_to_srvr_ip_adrs_var = (String)childHash.get("ADMD_TO_SRVR_IP_ADRS");
myList.add((String)childHash.get("ADMD_TO_SRVR_IP_ADRS"));
%>
<SCRIPT LANGUAGE="JavaScript">

</SCRIPT>

<%
iCount++;
childHash.clear();
childHash = null;
}

}

enumHash = null;
server_ip.clear();
server_ip = null;
}

please help

Vivek s.

You should firstly add all the admd_to_srvr_ip_adrs_var to a Set and only than traverse the Set and display.

--
:alex |.::the_mindstorm::.

Originally posted by Kashif Riaz:
Wrong choice of data structure. You should have used a HashMap, which does not allow duplicates and automatically replaces any items already in the Map.

Why not use a Set rather than a Map?