In Java we have Integer.toBinaryString(int) which returns binary string representing the integer.How to represent for numbers larger than Integer.MAX_VALUE? For example,double d = Math.pow(10,50),how to obtain binary string for d ?

Note that the java.lang.Double class has the doubleToLongBits method that returns a long value and that the Long class has the toBinaryString method. You really should have a copy of the JavaDocs unpacked on your hard drive and get familiar with using it - it saves lots of time. Bill

Arjunkumar Shastry
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I think it won't handle the big number Math.pow(10,100).The only option is now to use,java.math.BigInteger.

William Brogden
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The doubleToLongBits method will handle any double - the reason being that it simply takes the 8 bytes of a double and returns them as 8 bytes of a long. Thus the bits represent the entire IEEE 754 floating point double - sign, exponent and mantissa. Bill

I’ve looked at a lot of different solutions, and in my humble opinion Aspose is the way to go. Here’s the link: http://aspose.com