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execute batch files in java

Sanjay Sanghavi
Greenhorn

Joined: Jun 28, 2005
Posts: 1
Hi,

I have 2 batch files "run.bat" and "run1.bat". They reside in C:/bin/. Contents of these files are as follows: Observe that "run.bat" is calling "run1.bat".

Run.bat
@echo Sanjay
call run1

Run1.bat
@echo Sanghavi

My java class reside in E;/bin and it looks like...

main(String[] args)
{
String command = "c:/bin/run.bat";
Process child = Runtime.getRuntime().exec(command);
}

Result of this java code execution is that it prints "Sanjay" and then its not able to call "run1.bat"

This is because the directory where these batch files reside is different from the dir where my java class is. If I change "run.bat" as follows, it works fine and prints "Sanghavi".

Run.bat
@echo Sanjay
call c:/bin/run1

But I dont want to change the batch file instead is there a way I can achieve this with some code changes in java or some other way to do this?

Thanks in advance
Sanjay
Ernest Friedman-Hill
author and iconoclast
Marshal

Joined: Jul 08, 2003
Posts: 24184
    
  34

Hi,

Welcome to JavaRanch!

This ought to work as long as the directory in which the BAT files are located in on your PATH.


[Jess in Action][AskingGoodQuestions]
Lewin Chan
Ranch Hand

Joined: Oct 10, 2001
Posts: 214
Tried
"cmd /c c:/bin/run.bat"

instead? Like EFH says, it should work if the bat files are in the path.

You could change the run1.bat to do (assuming windows NT or better)


set CURDIR=%~dp0
echo Sanjay
call "%CURDIR%run2.bat"

Then provided both run1 and run2 are in the same directory, you should be able to put them anyway.


I have no java certifications. This makes me a bad programmer. Ignore my post.
 
 
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