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Increment Operator

Alpana Singh
Ranch Hand

Joined: Sep 27, 2005
Posts: 36
I came across this question.

public class static1{
public static void main (String args[])
{
int i=0;
i=i++;
i=i++;
i=i++;
System.out.println(i);
}
}

And the ouput generated is 0.I can't understand why?
Please help.
Tim McGuire
Ranch Hand

Joined: Apr 30, 2003
Posts: 820

The ++ is evaluated after the assignment.

so i starts out as zero.
i=i++; // assign the value of i as zero, then increment. The incremented value is not kept!

i is still zero for the next expression:
i=i++; // same as saying i=0

and so on

try it with i = ++i instead to see the difference.
Srinivasa Raghavan
Ranch Hand

Joined: Sep 28, 2004
Posts: 1228
Also have a look at these simple one
good one


Thanks & regards, Srini
MCP, SCJP-1.4, NCFM (Financial Markets), Oracle 9i - SQL ( 1Z0-007 ), ITIL Certified
Steve Morrow
Ranch Hand

Joined: May 22, 2003
Posts: 657

The ++ is evaluated after the assignment.
Not quite; the assignment happens *last*. The increment occurs after the expression "i++" is evaluated. That expression ("i++") evaluates to the original value of i, and the result is "remembered". If the result of the expression "i++" is stored back into i, it's as if nothing happened at all. Here's another example:



The right-hand expression is evaluated as follows, starting with the first i++, the second i++, then adding the results of those two expressions, then assigning *that* value to i...


[ September 30, 2005: Message edited by: Steve Morrow ]
Alpana Singh
Ranch Hand

Joined: Sep 27, 2005
Posts: 36
Thanks Steve,Tim and Raghavan for clearing this.
 
I agree. Here's the link: http://aspose.com/file-tools
 
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