Accessing data structure

[Jackie Davis]

Hi I am not sure how to solve this problem. I have the follwing code

    
// Vertex
float[] xyz = new float[3];
 
// Cube1
xyz[] c1vertices = new xyz[8];
 
c1vertices[0]=new xyz(-2, -2, -2);
c1vertices[1]=new xyz(-2, -2, 2);
c1vertices[2]=new xyz(-2, 2, -2);
c1vertices[3]=new xyz(-2, 2, 2);
c1vertices[4]=new xyz(2, -2, -2);
c1vertices[5]=new xyz(2, -2, 2);
c1vertices[6]=new xyz(2, 2, -2);
c1vertices[7]=new xyz(2, 2, 2);
 
// Cube2
xyz[] c2vertices = new xyz[8]
 
c2vertices[0]=new xyz(-7, -7, -7);
c2vertices[1]=new xyz(-2, -2, 2);
c2vertices[2]=new xyz(-2, 2, -2);
c2vertices[3]=new xyz(-2, 2, 2);
c2vertices[4]=new xyz(2, -2, -2);
c2vertices[5]=new xyz(2, -2, 2);
c2vertices[6]=new xyz(2, 2, -2);
c2vertices[7]=new xyz(2, 2, 2);
 

How do I access c1vertices[0] 's 'x' element (i.e -2)?

Thanks

[Keith Lynn]

You would need to set up a way to access the variables from within the class definition of xyz.

[Garrett Rowe]

Unless you have a class xyz that you are not showing, it looks like xyz is just a local reference to a float array. If that is the case, you aren't setting it up properly. What you want is an array of arrays.

final int ROWS = 8;
final int COLUMNS = 3;
float[][] cube1 = new float[ROWS][COLUMNS];
 
//Now you can add arrays of length 3 to every row in cube1
cube1[0] = {-2, -2, -2};
cube1[1] = {-2, -2, 2};
cube1[2] = {-2, 2, -2};
//...etc
 
//Then to access cube1's x coordinate at element 0
float coord = cube1[0][0];

[ March 05, 2006: Message edited by: Garrett Rowe ]