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cannot be resolved error - returning URL

joseph cooper
Ranch Hand

Joined: Nov 08, 2005
Posts: 44
I am trying to return an URL created from a string. I am getting an error on the return statement "site cannot be resolved". I am assuming that site is not being reconized as an URL? I am not seeing how to resolve this. Any help would be appreciated.


URL createURL(String urlString)
throws MalformedURLException
{
final String openNewInternetWindow = " target=_blank";
try
{
urlString = "http://www.google.com/";
urlString = urlString + openNewInternetWindow;
URL site = new URL(urlString);
}
catch(MalformedURLException me)
{
throw new MalformedURLException(me.getMessage());
}
return site;
} //createURL
Amit M Tank
Ranch Hand

Joined: Mar 28, 2004
Posts: 257
URL createURL(String urlString)
throws MalformedURLException
{
final String openNewInternetWindow = " target=_blank";
URL site = null;
try
{
urlString = "http://www.google.com/";
urlString = urlString + openNewInternetWindow;
site = new URL(urlString);
}
catch(MalformedURLException me)
{
throw new MalformedURLException(me.getMessage());
}
return site;
} //createURL


Amit Tank
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Rob Spoor
Sheriff

Joined: Oct 27, 2005
Posts: 19697
    
  20

Of course this will not work; the " target=_blank" string is NOT part of the URL - it should be another attribute to the A link element.


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