I understand that all variables (i.e. data members) inside an interface are final and static. Going by this logic, the following program should throw an error, but works perfectly! Kindly clarify why? interface inter1 { int i=10;//i is final? void dis(); } interface inter2 { int i=20; /* Reinitializing i again here. Compiler is expected to throw an error.*/ } class face implements inter2,inter1 { public void dis() { System.out.println("Interface 1 is called"); } public static void main(String ar[]) { face ob=new face(); ob.dis(); System.out.println(inter1.i); System.out.println(inter2.i); } }
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Regards,<br /> <br />Shakthi
deekasha gunwant
Ranch Hand
Joined: May 06, 2000
Posts: 396
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hi kumaresan,
look carefully : 1) u are initializing i two times but in two different interfaces. so being in two different interfaces they r not same. so compiler sees them as two different i's. & each of them is initialized once only. so it is perfectly okay.
2) the compiler will certainly give an error if in ur main method of face class u use any of the following statement inter1.i = 2; or inter1.i = 4; coz now u r trying to alter a final variable.
hope this helps do let me know ur response regards deekasha