Math.random() creates a random double between 0.0 to 1.0 (1.0 excluded). Suppose i want to generate numbers between 1 and 50 (both inclusive),
(int)Math.round(Math.random()*50) is the expression i will use. Will the expression definitely create 50? If the result of random() is 0.99... and it is multiplied by 50, and then if the round() creates a 50, then it is fine. I can understand this, but i would like somebody to confirm. Shree
>Math.random() creates a random double between 0.0 to 1.0 (1.0 >excluded). << correct<br /> >Suppose i want to generate numbers between 1 and 50 (both >inclusive), >(int)Math.round(Math.random()*50) will create uniform random numbers in the range of 0 to 50 (with 1/100 probability of being 0 or 50 and 1/50 probability of being ( 1, 2, 3, 4, ... or 49 ). >is the expression i will use. i would use 1 + (int) ( Math.random() * 50 ) which Math.random() yeilds a number 0.0 to 0.99999 * 50 yeilds 0.0 to 49.99999 (int) yeilds 0 to 49 1 + yeilds 1 to 50
sateesh donti
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Joined: Sep 25, 2000
Posts: 2
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Hi, An another way to do this .. (int) Math.ceil(Math.random() * 50)
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