This week's book giveaway is in the OO, Patterns, UML and Refactoring forum. We're giving away four copies of Refactoring for Software Design Smells: Managing Technical Debt and have Girish Suryanarayana, Ganesh Samarthyam & Tushar Sharma on-line! See this thread for details.

I have already gotten one good response to this one, but now I can't understand how to extract the digits so I can sum them together (2 + 3 + 4 =9). Anyone got any great idea? Here's the code I already got: public class Test{ public static void main(String[] args){ int i = 234; sumDigits(i);} private static void sumDigits(int digits){System.out.println("digits before calculation: " + digits);int sum = 0; sum += digits % 10; digits /= 10; System.out.println("sum: " + sum);System.out.println("digits after calculation: " + digits); }} Thanks!!!Mary Ellen

Hello, The first thing is to separate the digits. If you take a 3 digit number and divide by 100, your answer will be a single digit representing the hundreds place. Now, if you take that same 3 digit number and get the modulus of a division by 100, you will be left with the tens and units places, represented as a 2 digit number. Take that 2 digit number, divide by ten and you'll have the 10's place, the modulus of the 2 digit number divided by 10 will be the units place. Let's try 123.. 123 / 100 = 1 ( the hundreds place ) 123 % 100 = 23 ( the remainder ) 23 / 10 = 2 ( the tens place ) 23 % 10 = 3 ( the units place ) Sum up the hundreds, tens & units and you'll have your answer. or.....

hth. Pat B.

MaryEllen Volb
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Joined: Jan 31, 2001
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Yes, it did help so much.....thanks....I wouldn't be getting thru my class if not for all the help I find here!!!