i & i++ print same( int i) , how?

[karthik bhagnagarapu]

hi,

public class Test{
private int i;
Test(int ii){
i = ii;
}
public static void main(String[] args){
Test t = new Test(5);
1) System.out.println(t.i); // this prints 5
2) System.out.println(t.i++);// so does this, a 5.
}
}
now for 1) and 2) didn't i invoke methods on the object System.out? my guess the interpreter ignores the ++ sign,
but why? i hope someone can help me. thx in advance.

[Marilyn de Queiroz]

Originally posted by Gareth Leachman:
because it is postfix, the operating system will use t.i with its value of 5, and then increment i by 1. This is the nature of postfix operators.

which is why I recommend that you avoid writing your code this way. It can be confusing. Put the increment on a separate line.

[Magesh Lakshmi]

Try printing out the value of t.i after the statement
System.out.println( t.i++);
Then u will notice the value of t.i is incremented.
This is b'cos the evaluation in this case is from right to left, the variable is just printed first and incremented.

[Magesh Lakshmi]

oops..i made a verbal mistake..
the evaluation is from left to right.