try/catch cert guide quiz question???

[Otto Deckelman]

Another cert question, can anybody break this down?

<font size="+0">
class Question {
   public static void main(String[] args) {
      for(int i=0;i<10;++i) {
         try {
            if(i % 3 == 0) throw new Exception("E0");
            try {
               if(i % 3 == 1) throw new Exception("E1");
               System.out.println(i);
            }catch (Exception inner) {
               i *= 2;
            }finally{
               ++i;
            }
         }catch (Exception outer) {
            i += 3;
         }finally{
            ++i;
         }
      }
   }
}

Marilyn added code tags

[This message has been edited by Marilyn deQueiroz (edited April 20, 2001).]

[sai challa]

Originally posted by Otto Deckelman:
Another cert question, can anybody break this down?
class Question {
public static void main(String[] args) {
for(int i=0;i<10;++i) {
try {
if(i % 3 == 0) throw new Exception("E0");
try {
if(i % 3 == 1) throw new Exception("E1");
System.out.println(i);
}catch (Exception inner) {
i *= 2;
}finnaly{
++i;
}
}catch (Exception outer) {
i += 3;
}finally{
++i;
}
}
}
}

1.the for loop starts with i=0.It enters the first outer try block,and checks the condition i%3 i.e 0%3 =0,since the if condition is true ,an Exception("EO") is thrown,the control now goes to a catch block handling the exception and the inner try block is not entered.The catch block(Exception outer) handles the exception produced and i is incremented by 3 i.e i=0+3=3.The finally block is always executed and i is incremented again i.e i=3+1=4
Now control goes to the for loop ,since i<10 i is incremented by 1 i.e i=4+1=5.
2.Now the outer try block is entered i%3 i.e 5%3=2 which is not equal to 0.Hence if condition is skipped and control is transferred to the next statement i.e the inner try block here i%3 is evaluated i.e 5%3=2 which is not equal to 1 ,hence the if condition is skipped and control goes to the next statement and the value of i i.e 5 is printed. The finally block is always executed ,hence the inner finally block increments i to 6
and the outer finally block increments i to 7.
3.Now control comes to the for loop again and i is incremented to 8.Since i<10 ,the outer try block is entered i%3 is evaluated i.e 8%3=2 which is not 0,hence the inner try block is entered again i%3 is evaluated i.e 8%3=2 which is not equal to 1,the if condition is skipped and the next statement is executed which prints the value of i i.e 8. The finally block is always executed ,hence i is incremented to 9 in the inner finnaly block and 10 in the outer finally block .
4.Now the control goes to the for loop with i=10 ,therefore the condition i<10 fails and control goes out of for loop.
Hence output is 5,8