escape sequences

[Ronald Whalen]

Hi! Got a simple question. I am trying to print text to file. I am having trouble with this line:
out.println("errorMsg += \"'\n''\n'\"+(errCount+1)+\". Name not specified\";");
I keep getting new lines in the text file rather than having \n print out twice. I thought that placing it in single quotes would allow for the character literals to print out rather than the new line. any help would be appreciated.

Thanks!
Ronald

[Roy Tock]

Rather than use '\n', have you tried \\n?
This code:

public class Trial
{
    public static void main( String[] args )
    {
System.out.println(
            "errorMsg += \"\\n\\n\"+(errCount+1)+\". " +
            "Name not specified\";");
    }
}

yields this output:
C:\Temp>java Trial
errorMsg += "\n\n"+(errCount+1)+". Name not specified";
C:\Temp>

[Ronald Whalen]

Thanks for the reply. Tried that too. Finally got it to work by using the concat operator to break up the string along the lines of
..+"\\"+"n"+