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Package visibility

 
Willie Toma
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I don't understand this answer? Here is the Q&A.
What happens when you attempt to compile and run these two files in the same directory?
//File P1.java
package MyPackage;
class P1{
void afancymethod(){
System.out.println("What a fancy method");
}
}
//File P2.java
public class P2 extends P1{
afancymethod();
}
1) Both compile and P2 outputs "What a fancy method" when run
2) Neither will compile
3) Both compile but P2 has an error at run time
4) P1 compiles cleanly but P2 has an error at compile time
Answer:
4) P1 compiles cleanly but P2 has an error at compile time
Even though P2 is in the same directory as P1, because P1 was declared with the package statement it is not visible from P2
 
Adrian Yan
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Actaully, it's quite simple.
To use a package, you need to import it. If you add import MyPackage in P2.java, then it's fine.
Remember, package != directory.
 
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