asking question regarding string memory allocation in array

i have a question regarding string memory allocation in array given below:
int []arr=new int[6];
as in array each individual element(arr[0])will take 4 bytes n 4 for the referencing it to some memory.it means that the int array i just defined above will take 28 bytes rather than tking 24 bytes.i want to ask that
a)why 4 bytes are preserved for referencing
b)if int takes 4 bytes/element then how about long double, float n rest of other data types ,how much of data they will be saving.
c)i want to ask that either 4 bytes are used for referencing for only int or referencing into the all data types would be varying due to the types.
d)could you specify the differnt memory sizes used for different data types arrays
i hope that sir you would reply this asap.
take care
thank you very much in advance
with regards
kumar abhay

Kumar
Here si reference to the JLS section 4.2 that will answer your questions on the integer primitives and their sizes and range of values. Basically it is like this:

All but the char are signed. The char represents unicode characters in the range of 0 to 65535.
As far as the sizes of the arrays and the size of the reference to each array I dont know that it is actually specified by the language itself and may be up to the implementation of the JVM you're using. If I'm wrong I know someone will correct me...
hope that helps
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Dave
Sun Certified Programmer for the Java� 2 Platform
[This message has been edited by Dave Vick (edited October 20, 2001).]

thank u very much for ur reply but i act want to know the operation in array.i hope that u will help me for this
take care
with regards
kumar abhay

Kumar
I'm sorry I dont think I understand your question. What is it in the arrya you want to know? The array sizes and size of the reference to it?
Let me know

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Dave
Sun Certified Programmer for the Java� 2 Platform

Hello
What I understand from your Query is:
the Array is taking 28 bytes rather than 24 bytes is bec:
Arrays in Java are objects & object variables always store
refernces of the array & refernces are always stored with
integral value. Therefore:
int[] arr = new arr[6];
here, arr ---> references store as integer value --> 4 Bytes
arr[0] --> 4 bytes
arr[1] --> 4 bytes arr[2] --> 4 bytes
arr[3] --> 4 bytes arr[4] --> 4 bytes
arr[5] --> 4 bytes
which equals to 28 bytes in total
Infact, all reference variablei.e of objects will storewith the range of integer
b) the "reference variable" of float & double or any other datatype will store with an integer. but the array values will have the same size as of datatype like:
double arr[] = new double[6];
48+ 4 = 52 bytes

I hope ypui have understood & will help in the next two questions
Regards,
Marium

hi there,
thank u very much miss marium for solving my problem.u mean to say that int array takes 4 bytes/element & float n double takes 8 bytes/element.i hope that your help will be there in the furure too.
take care
with regards
kumar abhay