abstract method call

[Gyutae Kim]

i have a piece of code that looks like this
abstract public class super
{
public void meth(){absMeth();}
abstract void absMeth();
}
public class sub extends super
{
protected void absMeth(){print something}
}
then when i run the meth method of sub nothing gets printed out shouldnt this work?
[ August 07, 2002: Message edited by: Gyutae Kim ]
[ August 07, 2002: Message edited by: Gyutae Kim ]

[Michael Morris]

Hi Gyutae,
Try this:

public class TestSuper {
    public static void main(String[] args) {
        Super s = new Sub();
        s.meth();
    }
}
abstract class Super {
    public void meth() {
        absMeth();
    }
    abstract void absMeth();
}
class Sub extends Super {
    protected void absMeth() {
        System.out.println("something");
    }
}

Hope this helps,
Michael Morris

[Dan Chisholm]

Gyutae,
You have attempted to use the keyword "super" as a class identifier. You need to change the name of your class.
If you want to put both class declarations in the same file, then you need to make sure that only one is declared public.

[Dirk Schreckmann]

then when i run the meth method of sub nothing gets printed out shouldnt this work?
Yes, Gyutae, such a structure should work. You perhaps have an error in your code. What is the code that you're trying to compile and run?