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javac -d

 
Paul Keohan
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I use this to compile a class but why do I not see the .class version being set into the appropriate directory? When I do this, I get no .class file. If I compile without the -d, the .class version will end up in the same directory as the .java version.
 
Ronald Schindler
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Into which directory are you trying to put the class file when compiling?
 
Paul Keohan
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It doesn't seem to make a difference. If I have a package com.test in the class and I try to compile with javac -d com\test cl.java it will say something like you can't compile into com\test\com\test. All I want to do is compile a class from the dos prompt and see it end up in the correct package/directory.
Paul
 
Dave Landers
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-d is going to be the "base" directory. Like, the same thing that you'd use in CLASSPATH.
So if you have a class called MyJunk in package "com.foo", and you want the thing to end up in /home/devel/classes/com/boo/MyJunk.class then you compile with javac -d /home/devel/classes MyJunk.java
and you'd execute it with
javac -classpath /home/devel/classes com.foo.MyJunk
 
It is sorta covered in the JavaRanch Style Guide.
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