This week's giveaway is in the Spring forum. We're giving away four copies of REST with Spring (video course) and have Eugen Paraschiv on-line! See this thread for details.

As far as I know, such a method is not in the standard API (nor is something that defines a Line to begin with). I'd bet that you could write one without too much difficulty. Wanna give it a try?

yes it was easy, but it wasn't what i need. so i decided to post what i need to do: Graham's scan algorithm. find if interior angle formed by Pa, Pb , Pc is greater than or equal to 180 degrees. i stopped here and can't think of nothing. it's the only thing left to do. could you suggest something to move on? thank you.

There is an easy algorithm for testing whether a point is on the left of a line. If you apply that to the two points then you can find out whether the two points are on opposite sides of the line. Then the line through the two points must cut the first line. Problem is I can't find a book I know has that algorithm (Haskel School of Expression). I'll keep looking but I'm sure the algorithm can be found with help of Google. -Barry

Or: A line can be represented in the form: F( x, y ) = a * x + b * y + c = 0 for a suitable choice of coefficients a, b, c. F( s , t ) == 0 when ( s , t ) is on the line. F( s , t ) > 0 when ( s , t ) is below the line. F( s , t ) < 0 when ( s , t ) is above the line. Maybe that will help. -Barry