How to create a color array?

[Samuel Fitzpatrick]

Question: I am trying to declare and assign values to a color array using sRGB values in one line.
I have found that
Color[] c1 = {Color.RED,Color.WHITE,Color.BLUE};
works.
But how do I get
Color[] c2 = {(255,0,0),(255,255,255),(0,0,255)};
to work?
Currently I have
Color[] c3 = new Color[3];
...
c3[0] = new Color(255,0,0);
c3[1] = new Color(255,255,255);
c3[2] = new Color(0,0,255);
but, would like this in one line. Thanks.

[Jim Yingst]

Well, there's

    Color[] c2 = {new Color(255,0,0),new Color(255,255,255),new Color(0,0,255)};

But that's as compact as it gets, I think.

[Samuel Fitzpatrick]

thanks, that was exactly what I was looking for.

[Robbie shi]

Color[] c2 = {new Color(255,0,0),new Color(255,255,255),new Color(0,0,255)};
you should use constructor
Color(int ,int,int)
----
Robbies
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[Jim Yingst]

Isn't that what we're doing?