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rounding a number (ceiling)?

mark babcock
Greenhorn

Joined: Jun 26, 2002
Posts: 14
I'm trying to round an integer.
lets say I have:
x = 22;
y = (x/10);
y would return 2.2 I want it to round up to the next whole number no matter what the decimal value. I was looking for a ceiling function. But, can't seem to find anything that does this.
Greg Charles
Sheriff

Joined: Oct 01, 2001
Posts: 2771
    
  10

Math.ceil(num)
This takes a double argument and returns a double, though the return value will be equal to an integer, so you can just cast it.
Remember integer division will trucate to an integer, e.g.,

will print out 0. You may want to make x a double, or cast it to double before dividing.
 
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