rounding a number (ceiling)?

[mark babcock]

I'm trying to round an integer.
lets say I have:
x = 22;
y = (x/10);
y would return 2.2 I want it to round up to the next whole number no matter what the decimal value. I was looking for a ceiling function. But, can't seem to find anything that does this.

[Greg Charles]

Math.ceil(num)
This takes a double argument and returns a double, though the return value will be equal to an integer, so you can just cast it.
Remember integer division will trucate to an integer, e.g.,

int x  = 10;
System.out.println(x/22);

will print out 0. You may want to make x a double, or cast it to double before dividing.