hi folks, why this is a problem? short a, b, c; b = 3; b = 1; c = a + b; //raises an error Why? c = (short) a + b; //okay or int c = a + b; //okay thanks.
Paul Morano
Greenhorn
Joined: Jun 18, 2003
Posts: 7
posted
0
I believe it is because the addition promotes the shorts to int's. Or, the result of the addition is an int. I forget which.
Dirk Schreckmann
Sheriff
Joined: Dec 10, 2001
Posts: 7023
posted
0
The addition promotes the operands to ints is correct, sir! From The JLS (�5.6.2):
When an operator applies binary numeric promotion to a pair of operands, each of which must denote a value of a numeric type, the following rules apply, in order, using widening conversion (�5.1.2) to convert operands as necessary:
If either operand is of type double, the other is converted to double.
Otherwise, if either operand is of type float, the other is converted to float.
Otherwise, if either operand is of type long, the other is converted to long.
Otherwise, both operands are converted to type int.
[ June 22, 2003: Message edited by: Dirk Schreckmann ]
0
