parsing standard input

[Greg Schwartz]

I was wondering if someone could recommend a better way to parse integer values from standard input.
Currently, I am using BufferedInputReader that returns the input in the form of a string. I then pass the string to a StringTokenizer. I check each token using Integer.parseInt(tokenValue) . I am then putting the ints into an array for processing. I'm using an array instead of a vector because the Vector class wouldn't process ints and it seemed to be a hassle to convert to the Integer type.
If anyone has a cleaner way of going about doing this, please let me know.
Thanks!

[Jon Dornback]

you're using the same algorithm I would use. If you need a re-sizable array, use java.util.ArrayList (don't use Vector - most of what i've read warns against it). To put ints in to the ArrayList, use this in the tokenizing loop:

// assume numString is your tokenizer variable
//        array is instanceof ArrayList
int n = 0;
try{
   n = Integer.parseInt(numString);
   array.add(new Integer(n));
} catch (NumberFormatException nfe){
   // numString wasn't really a number
}
// ... then, to get the int at position i out of the list:
Integer theInt = (Integer)(array.get(i)); // must typecast back to Integer
int x = theInt.intValue();

[Greg Schwartz]

Jon -
Thanks so much for your advice! I'm glad to hear that I was pretty close. I didn't know about ArrayList so I'll be sure to use that in my code.
Thanks again,
Greg

[Karthikeyan Rajendraprasad]

Originally posted by Jon Dornback:

// assume numString is your tokenizer variable
//        array is instanceof ArrayList
int n = 0;
try{
   n = Integer.parseInt(numString);
   array.add(new Integer(n));
} catch (NumberFormatException nfe){
   // numString wasn't really a number
}
// ... then, to get the int at position i out of the list:
Integer theInt = (Integer)(array.get(i)); // must typecast back to Integer
int x = theInt.intValue();

[/QB]

one performance tip.
what you do is
1. get the number as String
2. convert it to int
3. convert to Integer just before adding to the Arraylt
4. while getting it back you convert it to int again.
why do you convert this no of times. instead you can check whether it is an integer or not and store the string value directly in the ArrayList and then convert it to int while getting it from the list.