Why this does not fail?

[Brian Smith]

hi folks,

public class MyThread extends Thread{
    String msg = "default" ;
    public MyThread(String s){
        msg = s ;
    }
    public void run( ){
        System.out.println(msg) ;
    }
    public static void main(String args[ ] ){
        new MyThread("String1").run();
        new MyThread("String2").run();
        System.out.println("end") ;
    }
}

i thought the program would fail compiling as we can not invoke run()method directly. but it works fine. WHY?
I would appreciate if someone explains me.
thanks.
[ July 29, 2003: Message edited by: Namaste Sathi ]

[Joel McNary]

There's nothing preventing you from calling run: it is delared as public. The Thread class's run method does nothing (unless it was created with a Runnable object); but in your subclass here, it does do something.

[Brian Smith]

Joel,
so it's not necessary true that we can't invoke run() method of a Thread directly. And also, we can't predict when the run()method gets excuted once the start() is invoked. right?

[Thomas Paul]

If you invoke the run() method then it is not running as a separate thread. run() is no different than any other method when invoked that way.