Plz help! string class question

[zoster gibrilian]

Hi,
I have to define by "hard coding!?" a 32-bit binary string that represents an IP address.
1)Can u help me with a command to do this?
2)What is the bit-length of the testNum string below?
string testNum = "10000010111101010001101100000010";
3)What is hard coding?
Thanks

[Ouaknin lionel]

I can't say I fully understood your question....
- Hard coding means putting a litteral value in the code instead of getting this value through user input or file.
- an IP address is made of 4 bytes. a byte = 8 bit. A byte in java has the type

byte b;

a byte can take a value from -127 to 127.
An integer is also encoded in 4 for bytes. You can put an IP address into an integer or an array of 4 bytes.
for the array it is simple:

  
byte b[]=new byte[4];
b[0]=(byte) 45;
b[1]=(byte) 12;
b[2]=(byte) -10;
b[3]=(byte) -125;

for an integer use hex values.here i'm a bit lost...

[Stan James]

Terms like "binary string" are always a bit ambiguous. You did show a correct string representation of 32 1s and 0s which sounds like what was asked for. Are you comfortable converting integer to binary and back?
IP addresses are usually given as 4 numbers, each between 0 and 255, like 11.96.8.175. You can make each number an 8 bit binary and get your 32 bit string.
IP doesn't always interpret the address as 8-bit chunks. I forgot the particulars as soon as my networking class was over, but it can use 6-bit chunks or 10 bits or whatever the addressing scheme of the day requires. Going that deep into addressing is about the only reason I can think of to worry about binary representations. Which means, I'm curious about what you're up to!