how to tell if a number is even or odd, if statement

[Brandi Love]

How can I tell whether or not a given integer is even or odd using java? Also, can I put an if statement within a while loop?
[ November 02, 2003: Message edited by: Brandi Love ]

[David Crossett]

I hope I'm not just blowing hot air, but this should be easy:

if ( number % 2 == 0 )
    isEven = true //this is an even number...nothing is left over after dividing by 2
else if ( number % 2 != 0 )
    isEven = false //this number is odd...
  

Hope that helps!

[William Barnes]

can I put an if statement within a while loop?

You can put anything you want inside a while loop.

[Wayne L Johnson]

Simplify David's code to:

if ( number % 2 == 0 )
   isEven = true; // even number: nothing is left over after dividing by 2
else // no need for additional condition
   isEven = false; //this number is odd...

In fact, this is a great place to use the syntax:

isEven = number % 2 == 0;

[William Barnes]

isEven = number % 2 == 0;  

That may be legal, but it isn't read-able.

[Thomas Paul]

How about:
isEven = number%2==0?true:false;

I actually found code similar to this in a program I was debugging.

[Jim Yingst]

[Wayne]: isEven = number % 2 == 0;
[Wililam]: That may be legal, but it isn't read-able.
It's not? Ummm... how about now?
boolean isEven = (number % 2 == 0);
[Tom]: isEven = number%2==0?true:false;
OK, now that one's pretty funny.

[S Perreault]

Originally posted by William Barnes:

isEven = number % 2 == 0;  

That may be legal, but it isn't read-able.

Actually writing code like this (instead of the first example) is one of the first ways to separate yourself from the newbie programmers. It is as readable as the first example, and much more concise.
Perogi.