One more question, then thats it I promise :) ...

[Brandi Love]

Okay this program is supposed to take any integer entered by a user, then strip off the individual digits and sum them up. I just can't work out this last error I keep getting. Any idea how to fix it? Heres the code and the error message...

 import java.io.*;
import java.text.*;
public class IntSum2
{
public static void main (String[] args)
throws java.io.IOException
{
String s1, s2;
int InputNum, count, NumChars, num, total;


InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(isr);
System.out.println("Please enter a positive integer:");
s1 = br.readLine();
NumChars = s1.length();
InputNum = Integer.parseInt(s1);
count = 1;
total = 0;
num = 0;
for (count = 1; count<=NumChars; count++) {
num = (InputNum / Math.pow(10, count) % 10);
System.out.println(num);
total = total + num;}
System.out.println("The total is " + total);
}
} 

C:\My Documents\Homework 6\IntSum2.java:32: possible loss of precision
found : double
required: int
num = (InputNum / Math.pow(10, count) % 10);
^
1 error
Not sure why its telling me loss of precision, I think the equation is okay the way it is. I didnt start getting the error untill I put Math.pow into the equation.

[Amit KumarS]

hiii..
If you go through JavaDocs then you will find that Math.Pow() return a double and in this case you need to are storing the value in an int datatype.
tgus according to Java when u r storing a bigger datatype into a smaller in which there is possibility of loss of precision then you need to explicitly type cast it..
so u can do this in any of the following manner and your error will be gone..

num = (int)(InputNum / (Math.pow(10, count)) % 10);
or 
num = (InputNum / ((int)Math.pow(10, count)) % 10);

i hope i have answered your question... if still in doubt please get back
Thanks
Amit

[Brandi Love]

wonderful, it compiles! thank you