Hi I have a big string. For example: bigString="This is big string. Big string is not small"; and i have small string: smallString="is"; and i have to find how many matches with small string i have in big one. As a result there should be 2 matches. I have searched the whole string class doc and nothing simple has not come to my mind - it can't be hard. So does anyone know any good methods to find a match of one string to another? thnx.
Joined: Jun 24, 2002
Is it your home work obviously ? Something like this:
[ December 01, 2003: Message edited by: Igor Ko ]
Joined: Nov 18, 2003
Yes - it's my homework at school and i'm really out of time. I remember the teacher showd this in class and it was so obvious that i didn't write it down - now i'm in deep ... I didn't understand the code quite clearly - so if u could add sine comments it would be nice. Allso ... String.regionMatches() - i don't understand what are the parameters for this fx and can i use it? ok thnx - need more help.
Joined: Oct 20, 2000
Take a look at these examples.
Output is 3. Matches all occurances of "is" even the one in "this"
Output is 2. But if bigstring had contained something like "Do not end a sentence with the word is." it would have returned 0 because of the fullstop. By using regular expressions we can get around that:
Returns 3. Similar to the first attempt - trying to match "is" also matches "this"
Joined: Oct 30, 2003
I'm a newbie, I have a question I'd like to ask, Is empty for loop " for(; a good programming style?
If a man take no thought at what is distant, he will find sorrow near at hand. ~ Confucius
I would not use an empty for loop. I use a for loop when i know (or can calculate) the number of iterations i need. if i want an infinate loop, with a break condition, i'd use
Better/worse/proper is a debate that will go on forever...
Never ascribe to malice that which can be adequately explained by stupidity.
Joined: Oct 11, 2003
Is there a way to count the number of times the smallString is found in reverse order as well? For example if the BigString = "Mississipi" and the SmallString = "is". The number of occurrences would be 4. Counting the occurrences of "si" as well. M(is)(s(i)s)(si)pi.