Outputing Binary Numbers

[Joe Hoppe]

I am trying to output binary numbers to the standard stream. The problem is that I want to display them in the mathematically correct format.
Using 7.5 as a decimal example, to display it as:
111.1
Do I have to write my own method to convert these, or is there a simpler way?
Thanks,
Joe Hoppe

[Dirk Schreckmann]

Welcome to JavaRanch, Joe!
If you're not already familiar with it, you'll definitely want to get to know the J2SE API Specification.
Notice that the Double class has a method or two that you might find useful - doubleToLongBits and doubleToRawLongBits. If you want to see the bits that either of these outputs, try a simple example such as the following.

public class Foo 
{
  public static void main(String[] args) 
  {
    double number = 7.5;
    System.out.println(Long.toBinaryString(Double.doubleToLongBits(number)));
    System.out.println(Long.toBinaryString(Double.doubleToRawLongBits(number)));
  }
}

If you understand the IEEE 754 floating point bit pattern, then you should be able to figure something out.
Otherwise, it wouldn't really be all that much much to write a simple algorithm to convert the number "by hand".
Let us know how you make out.
Good luck.

[Joe Hoppe]

That's not a bad idea about converting from from the IEEE 754 Standard... I didn't think of that.
But I decided to do it manually. On the positive side (opposing my wasting time), it gives me a little greater control over the output.
Thanks