This week's book giveaway is in the OCAJP 8 forum. We're giving away four copies of OCA Java SE 8 Programmer I Study Guide and have Edward Finegan & Robert Liguori on-line! See this thread for details.

Hello all,there is a program. I think the answer is 1+2+2+3+3+3+4+4+4+4+5+5+5+5+5=55,but the correct answer is 35.Can anyone tell me why,I,m confused about it. Thanks a lot.

Originally posted by E Ma: Hello all,there is a program. public class Test{ public static void main(String[] args){ int i,j,s=0; for(i=1;i<=5;++i) for(j=1;j<=i;++j) s+=j; System.out.println(s); } }

In the above code on the first iteration i=1 and j =1 and therefore s = 1. On to the second iterartion now i =2 but in the first loop of j, j is set back to one and hence j loops twice. So we s+= 1 and s+=2 giving s =4. On to the third, fourth and fifth iterations of the i loop and the same logic applies. So the final sum for s would be : 0+1+1+2+1+2+3+1+2+3+4+1+2+3+4+5 = 35

Hi, Welcome to JavaRanch! You're adding up the values of j, not i. When i is 1, j will be 1. When i is 2, j will be 1 and 2. When i is 3, j will be 1, 2, and 3, etc -- not 3, 3, and 3 as your expected solution assumes. You'd get the answer you expected if you added up the value of i at every iteration instead of the value of j.

Hi .... First iteration i=1 and j =1, thus s = 1. Second iterartion now i =2, first loop of j, j = 1 and thus j loops twice. So s+= 1 and s+=2 giving s =4. and thus iterative process for further loop Following are the number added 0+1+1+2+1+2+3+1+2+3+4+1+2+3+4+5 = 35