# Handling NaN.....

Will Carpenter

Greenhorn

Posts: 26

posted 11 years ago

- 0

Given the following:

public class TrivialApplication

{ public static void main(String args[])

{

double A = 16, B = 5, C = 9;

double num;

num = ( -B + Math.sqrt( (B*B) - (4*A*C) ) ) / (2*A);

System.out.println(num);

num = ( -B - Math.sqrt( (B*B) - (4*A*C) ) ) / (2*A);

System.out.println(num);

}

}

The good ole quadratic formula!

Of course, when I run the above the displays say NaN. (Not a number, because you can't use Math.sqrt to find the root of a negative number.)

What'd I'd like to do is say "If num is NaN, move 0 to num", but how do I use NaN in an expression?

public class TrivialApplication

{ public static void main(String args[])

{

double A = 16, B = 5, C = 9;

double num;

num = ( -B + Math.sqrt( (B*B) - (4*A*C) ) ) / (2*A);

System.out.println(num);

num = ( -B - Math.sqrt( (B*B) - (4*A*C) ) ) / (2*A);

System.out.println(num);

}

}

The good ole quadratic formula!

Of course, when I run the above the displays say NaN. (Not a number, because you can't use Math.sqrt to find the root of a negative number.)

What'd I'd like to do is say "If num is NaN, move 0 to num", but how do I use NaN in an expression?

Jim Yingst

Wanderer

Sheriff

Sheriff

Posts: 18671

Ben Buchli

Ranch Hand

Posts: 83

posted 11 years ago

- 0

Hey, looks like an assignment I once had.

Why dont you just check the discriminant and if its less than zero you will have to create an imaginary number. I dont know however if you are required to do that (it's not a biggie though).

discriminant: ( bx * bx ) - ( 4 * ax * c )

so if you want to assign zero (is that what you mean by "move zero to num" ?) instead of creating an imaginary number, try something like this:

public class TrivialApplication

{ public static void main(String args[])

{

double A = 16, B = 5, C = 9;

double num;

//added this part to your code: check whether discr. is neg. nbr

//if so, execute following code, otherwise go to "else"

if ( ( B * B ) - ( 4 * A * C ) < 0 )

{

num = ( -B + Math.sqrt( (B*B) - (4*A*C) ) ) / (2*A);

System.out.println(num);

num = ( -B - Math.sqrt( (B*B) - (4*A*C) ) ) / (2*A);

System.out.println(num);

} else

num = 0;

}

}

[ March 27, 2004: Message edited by: Ben Buchli ]

[ March 28, 2004: Message edited by: Ben Buchli ]

Why dont you just check the discriminant and if its less than zero you will have to create an imaginary number. I dont know however if you are required to do that (it's not a biggie though).

discriminant: ( bx * bx ) - ( 4 * ax * c )

so if you want to assign zero (is that what you mean by "move zero to num" ?) instead of creating an imaginary number, try something like this:

public class TrivialApplication

{ public static void main(String args[])

{

double A = 16, B = 5, C = 9;

double num;

//added this part to your code: check whether discr. is neg. nbr

//if so, execute following code, otherwise go to "else"

if ( ( B * B ) - ( 4 * A * C ) < 0 )

{

num = ( -B + Math.sqrt( (B*B) - (4*A*C) ) ) / (2*A);

System.out.println(num);

num = ( -B - Math.sqrt( (B*B) - (4*A*C) ) ) / (2*A);

System.out.println(num);

} else

num = 0;

}

}

[ March 27, 2004: Message edited by: Ben Buchli ]

[ March 28, 2004: Message edited by: Ben Buchli ]