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Odd Left Shift

 
Greenhorn
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Following gives a result of 10. I was expecting 0. I understand byte is converted to int before shift and int is 32 bit, but thought would have all 0 bits. Any advice appreciated. I realise (5<<1) also gives 10.
public class Q5
{
public static void main(String args[])
{
byte b = 5;
System.out.println(b<<33);
}
}
 
author and iconoclast
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If you shift by more than 31 bits, the shift is taken modulo-32; shifting by 33 bits is equivalent to shifting by 1 bit. JLS section 15.19:

If the promoted type of the left-hand operand is int, only the five lowest-order bits of the right-hand operand are used as the shift distance. It is as if the right-hand operand were subjected to a bitwise logical AND operator & (�15.22.1) with the mask value 0x1f. The shift distance actually used is therefore always in the range 0 to 31, inclusive.

 
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