Okay... So, I'm doing an assignment for my java class, and our teacher has written a halstead metrics program for us as a template. We're to modify the program to apply to the java language, i.e. take a simple program and count all the different "verbs" and "nouns", then compute the halstead metrics for it. The problem is recognizing symbols that do not have spaces surrounding them, i.e. args[], I need to count args, [, and ]. Now, is there anyway to write a file containing all the same information while putting spaces before and after such symbols... it's not implausable to write an if statement to find a [ and put spaces on either side. But, because of how he's written the template using StringBuffer is going to be a massive amount of work and re-design of the template, which is to be avoided. And, replace() only works with characters... so... any ideas? Thanks!
I'm not sure whether I understood your task, but I guess you're mixing 'alphabetic characters' and 'char' from a programmers view. If you get a line of code to parse, and firstly count the special characters, like ,;[](...; In the next step you could replace every of them with a blank, wich is a char from a programmers view. Then all your tokens should be seperated.
I don't know what a halstead metrics program is, but if you just want to put spaces around non-word characters [A-Za-z0-9], try this (needs java v1.4+)
Andrew M.
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Joined: Apr 07, 2004
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... Okay... this is pretty much what it's boiling down to now... I have one large string... and within that string are, for an example, right and left parenthesis... I have to put spaces," ", before and after every one of them. I'm not sure I quite grasp that above block of code, but, I'll give it a whirl.
Andrew M.
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Oh... and, will replaceAll work with a normal string aswell as a stringbuffer?
Michael Dunn
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replaceAll() is a method of the String class to work with a StringBuffer you would need to call the toString() method first if all you need is to find parentheses/braces/brackets ()/{}/[] try this (delete any sets not required) str = str.replaceAll("[\\[\\]\\{\\}\\(\\)]"," $0 ");
Andrew M.
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Joined: Apr 07, 2004
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that single line of code means wonders to me, thank you.
Andrew M., Welcome to JavaRanch! We ain't got many rules 'round these parts, but we do got one. Please change your display name to comply with The JavaRanch Naming Policy. We'd like more than an initial for the last name. Thanks Pardner! Hope to see you 'round the Ranch!
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