Converting an INT to a CHAR ?

[Kristian Andersson]

I'm trying to find out what ASCII-numbers are equalent to the letters:
"c", "o", "m". Perhaps not the easiest way, but I set up this code:

for (int f = 0; f < 256; f++)
{
  char c = f;
  System.out.println(c);
}

I knew it wouldn't work. Somehow, I need to convert the int to a char, or whatever. Almost like the Integer-thing, but not quite. (And yes, I don't know the exact words or terms for "it". If anyone wants to explain it to me - go ahead.)
And by the way. If it would've worked, then I would've counted every printout on the screen until I stumbled upon the desired letters.
[ May 10, 2004: Message edited by: Kristian Andersson ]

[Joel McNary]

Your code is fine as it is, you just need to explicitly cast the int to a char (Since an int is larger than a char, the compiler thinks that you made a mistake. Explicit casts are ways of telling the compiler "I know what I'm doing ... I think )

    public static void main(String[] argv){
        for (int f = 0; f < 256; f++){
            char c = (char) f;
            System.out.println(c);
        }
int test = 'c';
System.out.println(" c = " + test);
test = 'm';
System.out.println(" m = " + test);
test = 'o';
System.out.println(" o = " + test);
        return;
    }

BTW, the last series of lines will do what you are looking for without having to search the printout.

[Dirk Schreckmann]

I'm trying to find out what ASCII-numbers are equalent to the letters:
"c", "o", "m".
If you're not necessarily looking for a code-based solution, I frequently peek at asciitable.com for ascii character info.