Getting unexpected Result.

[Al sha]

Hi ,

Can anyone please explain why am I getting "test2 called" as output instead of throwing null pointer exception for the code mentioned below.

Thanx in advance.

---------------------------------------------------------------------------

public class TestSingle{

public static void main(String st[]){
TestSingle ts = new TestSingle();
ts=null;
ts.test2();
}

public static void test2(){
System.out.println("test2 called");
}

}
---------------------------------------
Output:test2 called.
---------------------------------------

[Marilyn de Queiroz]

Because the test2 method is static, it does not depend on an instance of TestSingle to run.

public class TestSingle{
    
    public static void main( String st[] ){
        test2();
    }
    
    public static void test2(){
        System.out.println("test2 called");
    }
     
}  

will work the same way as what you have.

[Al sha]

Suppose we are invoking test2() in another class like one below

public class TestSingle1{

public static void main(String args[]){
TestSingle ts2 = new TestSingle();
ts2 = null;
ts2.test2();
}

}


Even this prints out the message in test2(), though the variable ts2 is made to null.
Is it because of the static nature of the method test2() ?

[Marilyn de Queiroz]

It is because of the static nature of the method test2(). If you make the test2() method into an instance method, you will see what you expected.

[Al sha]

Hi Marilyn,

Thanks for u r valuable info and timely help.

Regards

Al Sha